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5a^2-16a-45=0
a = 5; b = -16; c = -45;
Δ = b2-4ac
Δ = -162-4·5·(-45)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-34}{2*5}=\frac{-18}{10} =-1+4/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+34}{2*5}=\frac{50}{10} =5 $
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